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Josephus Problems
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Josephus argorithsm.  here are people standing in a  circle  waiting to be executed. The counting out begins at some point in the circle and proceeds around the circle in a fixed direction. In each step, a certain number of people are skipped and the next person is executed. The elimination proceeds around the circle (which is becoming smaller and smaller as the executed people are removed), until only the last person remains, who is given freedom.
tkhanh
2016-08-23
0
1
Java_examples
no vote
Some examples about Java language.  1. ax + b = c 2. ax2 + bx + c = 0 3. a1x1 + b1X2 = c1     a2x1 + b2x2 = c2 4. a1x1 + b1x2 + c1x3 = d1      a2 x1 + b2x2 + c2x3 = d2     a3 x1 + b3x2 + c3x3 = d13
tkhanh
2016-08-23
0
1
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