CUBIC SPLINE ALGORITHM
2016-08-23
0 0 0
no vote
Other
Earn points
TO CONSTRUCT THE CUBIC SPLINE INTERPOLANT S FOR
THE FUNCTION F, DEFINED AT THE NUMBERS
X(0) < X(1) < ... < X(N), SATISFYING
S''(X(0)) = S''(X(N)) = 0:
INPUT: N; X(O),X(1), ...,X(N); EITHER GENERATE
A(I) = F(X(I)) FOR I = 0,1, ...,N OR INPUT
A(I) FOR I = 0,1, ...,N.
OUTPUT: A(J),B(J),C(J),D(J) FOR J = 0,1, ...,N-1.
NOTE: S(X) = A(J) + B(J)*(X-X(J)) + C(J)*(X-X(J))**2 +
D(J)*(X-X(J))**3 FOR X(J) < X < X(J+1)
THE FUNCTION F, DEFINED AT THE NUMBERS
X(0) < X(1) < ... < X(N), SATISFYING
S''(X(0)) = S''(X(N)) = 0:
INPUT: N; X(O),X(1), ...,X(N); EITHER GENERATE
A(I) = F(X(I)) FOR I = 0,1, ...,N OR INPUT
A(I) FOR I = 0,1, ...,N.
OUTPUT: A(J),B(J),C(J),D(J) FOR J = 0,1, ...,N-1.
NOTE: S(X) = A(J) + B(J)*(X-X(J)) + C(J)*(X-X(J))**2 +
D(J)*(X-X(J))**3 FOR X(J) < X < X(J+1)
fortran
算法
插值
三次
Related Source Codes
Deform secondary development
0
0
no vote
Classic Interview Questions for Digital City Front
0
0
no vote
HDU-2553 N Queen Question
0
0
no vote
unifiber-VUMAT
0
0
no vote
Artificial fish school algorithm
0
0
no vote
No comment