Coordinate inverse computation
2016-08-23
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Dim pb As Double
Dim ds As Double
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim x1 As Double
Dim y1 As Double
Dim x2 As Double
Dim y2 As Double ' define the start and end coordinates as double-precision floating point type
Dim s As Double ' define a distance of double-precision floating point type
Dim d As Integer ' define degrees for plastic surgery
Dim f As Integer ' define into plastic
Dim m As Integer ' define seconds for plastic surgery
Dim x As Double \'x increases for double-precision floating point type
Dim y As Double \'y increases for double-precision floating point type
Dim fwj As Double \' azimuth of variables for double-precision floating point type
Dim PI As Double \' PI as double-precision floating point type
pi = 3.14159265358979
x1 = Val(textbox1. Text) \' enter the starting x coordinate
y1 = Val(textbox2. Text) \' input
Dim ds As Double
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim x1 As Double
Dim y1 As Double
Dim x2 As Double
Dim y2 As Double ' define the start and end coordinates as double-precision floating point type
Dim s As Double ' define a distance of double-precision floating point type
Dim d As Integer ' define degrees for plastic surgery
Dim f As Integer ' define into plastic
Dim m As Integer ' define seconds for plastic surgery
Dim x As Double \'x increases for double-precision floating point type
Dim y As Double \'y increases for double-precision floating point type
Dim fwj As Double \' azimuth of variables for double-precision floating point type
Dim PI As Double \' PI as double-precision floating point type
pi = 3.14159265358979
x1 = Val(textbox1. Text) \' enter the starting x coordinate
y1 = Val(textbox2. Text) \' input
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